Q16
Invariant lines and eigenvalues and vectors
Diagonalize a matrix explicitly
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We fix two symplectic forms $\omega$ and $\omega _ { 1 }$ on $E$, and let $u \in \mathrm{GL}(E)$ be the unique automorphism such that $\omega_1(x,y) = \omega(u(x),y)$ for all $(x,y) \in E^2$. We assume that $E$ is of dimension 4 and that $u$ has no real eigenvalue. Let $\mathcal{B}$ be a basis of $E$ such that $\operatorname{Mat}_{\mathcal{B}}(\omega) = J_4$, and let $U \in \mathcal{M}_4(\mathbb{R})$ be the matrix of $u$ in $\mathcal{B}$. Let $\lambda \in \mathbb{C} \backslash \mathbb{R}$ and $Z, Y \in \mathbb{C}^4$ be as in question 15.
Let $Z _ { 1 } , Z _ { 2 } , Y _ { 1 } , Y _ { 2 }$ be vectors of $\mathbb { R } ^ { 4 }$ such that $Z = Z _ { 1 } + i Z _ { 2 }$ and $Y = Y _ { 1 } + i Y _ { 2 }$. Let $\left( z _ { 1 } , z _ { 2 } , y _ { 1 } , y _ { 2 } \right) \in E ^ { 4 }$ have coordinates respectively $Z _ { 1 } , Z _ { 2 } , Y _ { 1 } , Y _ { 2 }$ in the basis $\mathcal { B }$. Show that $\widetilde { \mathcal { B } } : = \left( z _ { 1 } , z _ { 2 } , y _ { 1 } , - y _ { 2 } \right)$ is a basis of $E$.