We define a sequence of polynomials $\left( A _ { n } \right) _ { n \in \mathbb { N } }$ satisfying $A _ { 0 } = 1 , A _ { n + 1 } ^ { \prime } = A _ { n }$ and $\int _ { 0 } ^ { 1 } A _ { n + 1 } ( t ) d t = 0$ for every $n \in \mathbb { N }$. For $n \geqslant 2$, the variations of $A_n$ on $[0,1]$ are known, in particular:
- If $n \equiv 2 \bmod 4$, then $A _ { n } ( 0 ) = A _ { n } ( 1 ) > 0 > A _ { n } \left( \frac { 1 } { 2 } \right)$.
- If $n \equiv 0 \bmod 4$, then $A _ { n } ( 0 ) = A _ { n } ( 1 ) < 0 < A _ { n } \left( \frac { 1 } { 2 } \right)$.
- If $n \equiv 1 \bmod 4$, then $A _ { n } ( 0 ) = A _ { n } \left( \frac { 1 } { 2 } \right) = A _ { n } ( 1 ) = 0$; $A _ { n } < 0$ on $]0 , \frac{1}{2}[$ and $A _ { n } > 0$ on $]\frac{1}{2} , 1[$.
- If $n \equiv 3 \bmod 4$, then $A _ { n } ( 0 ) = A _ { n } \left( \frac { 1 } { 2 } \right) = A _ { n } ( 1 ) = 0$; $A _ { n } > 0$ on $]0 , \frac{1}{2}[$ and $A _ { n } < 0$ on $]\frac{1}{2} , 1[$.
a) Show that for $n \geqslant 2$, the variations of the polynomials $A _ { n }$ on $[ 0,1 ]$ correspond to the four cases described above.
b) For every $n \in \mathbb { N } ^ { * }$ and every $x \in [ 0,1 ]$, show that $\left| A _ { 2 n } ( x ) \right| \leqslant \left| a _ { 2 n } \right|$ and $\left| A _ { 2 n + 1 } ( x ) \right| \leqslant \frac { \left| a _ { 2 n } \right| } { 2 }$.