For a real number $\mathbf { x }$, $$\sqrt { \frac { \sqrt { x } + 2 } { \sqrt { x } - 2 } } = \sqrt { x } + 2$$ Given that, what is x? A) 3 B) 4 C) 5 D) 6 E) 7
For a real number $\mathbf { x }$,
$$\sqrt { \frac { \sqrt { x } + 2 } { \sqrt { x } - 2 } } = \sqrt { x } + 2$$
Given that, what is x?\\
A) 3\\
B) 4\\
C) 5\\
D) 6\\
E) 7