jee-main 2024 Q71

jee-main · India · session2_06apr_shift2 Function Transformations

Let $f ( x ) = \frac { 1 } { 7 - \sin 5 x }$ be a function defined on $\mathbf { R }$. Then the range of the function $f ( x )$ is equal to:
(1) $\left[ \frac { 1 } { 7 } , \frac { 1 } { 6 } \right]$
(2) $\left[ \frac { 1 } { 8 } , \frac { 1 } { 5 } \right]$
(3) $\left[ \frac { 1 } { 7 } , \frac { 1 } { 5 } \right]$
(4) $\left[ \frac { 1 } { 8 } , \frac { 1 } { 6 } \right]$

Let $f ( x ) = \frac { 1 } { 7 - \sin 5 x }$ be a function defined on $\mathbf { R }$. Then the range of the function $f ( x )$ is equal to:\\
(1) $\left[ \frac { 1 } { 7 } , \frac { 1 } { 6 } \right]$\\
(2) $\left[ \frac { 1 } { 8 } , \frac { 1 } { 5 } \right]$\\
(3) $\left[ \frac { 1 } { 7 } , \frac { 1 } { 5 } \right]$\\
(4) $\left[ \frac { 1 } { 8 } , \frac { 1 } { 6 } \right]$

Paper Questions

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