In a triangle $\mathrm { ABC } , \mathrm { BC } = 7 , \mathrm { AC } = 8 , \mathrm { AB } = \alpha \in \mathrm { N }$ and $\cos \mathrm { A } = \frac { 2 } { 3 }$. If $49 \cos ( 3 \mathrm { C } ) + 42 = \frac { \mathrm { m } } { \mathrm { n } }$, where $\operatorname { gcd } ( \mathrm { m } , \mathrm { n } ) = 1$, then $\mathrm { m } + \mathrm { n }$ is equal to $\_\_\_\_$