In the given situation force at center on $\mathbf { 1 ~ k g }$ mass is $\mathbf { F } _ { \mathbf { 1 } }$. Now if $\mathbf { 4 ~ m }$ and 3 m is interchanged the force is $\mathrm { F } _ { 2 }$. Given : $\frac { \mathrm { F } _ { 1 } } { \mathrm {~F} _ { 2 } } = \frac { 2 } { \sqrt { \mathrm { a } } }$. Find $\alpha$.
(A) $\alpha = 1$
(B) $\alpha = 3$
(C) $\alpha = 5$
(D) $\alpha = 7$