\textbf{105-} If $\alpha, \beta$ are the roots of the equation $2x^2 - 3x - 4 = 0$, the equation whose roots are $\left\{\dfrac{1}{\alpha}+1,\ \dfrac{1}{\beta}+1\right\}$ is:
\begin{itemize}
\item[(1)] $4x^2 - \Delta x + 1 = 0$
\item[(2)] $4x^2 - 3x + 1 = 0$
\item[(3)] $4x^2 - \Delta x - 1 = 0$
\item[(4)] $4x^2 - 3x - 1 = 0$
\end{itemize}