\textbf{198-} The work function of a metal is $2\,\text{eV}$. If light with frequency $2\times10^{15}\,\text{Hz}$ shines on this metal, the stopping voltage is $V_0$. If light with frequency $V_0$ shines on the metal, the stopping voltage will be how many volts? $\left(h = 4\times10^{-15}\,\text{eV.s}\right)$
(1) $1$ \hfill (2) $2$ \hfill (3) $\dfrac{1}{2}$ \hfill (4) $\dfrac{1}{3}$