Q66. The vertices of a triangle are $\mathrm { A } ( - 1,3 ) , \mathrm { B } ( - 2,2 )$ and $\mathrm { C } ( 3 , - 1 )$. A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :\\
(1) $x + y + ( 2 - \sqrt { 2 } ) = 0$\\
(2) $- x + y - ( 2 - \sqrt { 2 } ) = 0$\\
(3) $x + y - ( 2 - \sqrt { 2 } ) = 0$\\
(4) $x - y - ( 2 + \sqrt { 2 } ) = 0$