Q51. The de-Broglie's wavelength of an electron in the $4 ^ { \text {th } }$ orbit is $$\pi \mathrm { a } _ { 0 } \cdot \left( \mathrm { a } _ { 0 } = \text { Bohr's radius } \right)$$
Q51. The de-Broglie's wavelength of an electron in the $4 ^ { \text {th } }$ orbit is
$$\pi \mathrm { a } _ { 0 } \cdot \left( \mathrm { a } _ { 0 } = \text { Bohr's radius } \right)$$