Q77. If the solution $y = y ( x )$ of the differential equation $\left( x ^ { 4 } + 2 x ^ { 3 } + 3 x ^ { 2 } + 2 x + 2 \right) \mathrm { d } y - \left( 2 x ^ { 2 } + 2 x + 3 \right) \mathrm { d } x = 0$ satisfies $y ( - 1 ) = - \frac { \pi } { 4 }$, then $y ( 0 )$ is equal to :\\
(1) $\frac { \pi } { 2 }$\\
(2) $- \frac { \pi } { 2 }$\\
(3) 0\\
(4) $\frac { \pi } { 4 }$