jee-main 2025 Q88

jee-main · India · session2_02apr_shift1 First order differential equations (integrating factor)
Q88. Let the solution $y = y ( x )$ of the differential equation $\frac { \mathrm { d } y } { \mathrm {~d} x } - y = 1 + 4 \sin x$ satisfy $y ( \pi ) = 1$. Then $y \left( \frac { \pi } { 2 } \right) + 10$ is equal to $\_\_\_\_$
Q88. Let the solution $y = y ( x )$ of the differential equation $\frac { \mathrm { d } y } { \mathrm {~d} x } - y = 1 + 4 \sin x$ satisfy $y ( \pi ) = 1$. Then $y \left( \frac { \pi } { 2 } \right) + 10$ is equal to $\_\_\_\_$\\