Let $O$ be the origin, the point $A$ be $z _ { 1 } = \sqrt { 3 } + 2 \sqrt { 2 } i$, the point $B \left( z _ { 2 } \right)$ be such that $\sqrt { 3 } \left| z _ { 2 } \right| = \left| z _ { 1 } \right|$ and $\arg \left( z _ { 2 } \right) = \arg \left( z _ { 1 } \right) + \frac { \pi } { 6 }$. Then\\
(1) area of triangle ABO is $\frac { 11 } { \sqrt { 3 } }$\\
(2) ABO is an obtuse angled isosceles triangle\\
(3) area of triangle ABO is $\frac { 11 } { 4 }$\\
(4) ABO is a scalene triangle