Let $F ( x ) = f ( x ) + f \left( \frac { 1 } { x } \right)$, where $f ( x ) = \int _ { 1 } ^ { x } \frac { \log t } { 1 + t } d t$. Then $F ( e )$ equals (1) $\frac { 1 } { 2 }$ (2) 0 (3) 1 (4) 2
Let $F ( x ) = f ( x ) + f \left( \frac { 1 } { x } \right)$, where $f ( x ) = \int _ { 1 } ^ { x } \frac { \log t } { 1 + t } d t$. Then $F ( e )$ equals\\
(1) $\frac { 1 } { 2 }$\\
(2) 0\\
(3) 1\\
(4) 2