If the sum of the series $1 ^ { 2 } + 2 \cdot 2 ^ { 2 } + 3 ^ { 2 } + 2 \cdot 4 ^ { 2 } + 5 ^ { 2 } + \ldots 2.6 ^ { 2 } + \ldots$ upto n terms, when n is even, is $\frac { n ( n + 1 ) ^ { 2 } } { 2 }$, then the sum of the series, when n is odd, is
(1) $n ^ { 2 } ( n + 1 )$
(2) $\frac { n ^ { 2 } ( n - 1 ) } { 2 }$
(3) $\frac { n ^ { 2 } ( n + 1 ) } { 2 }$
(4) $n ^ { 2 } ( n - 1 )$

The sum of the series $$\frac{1}{1+\sqrt{2}} + \frac{1}{\sqrt{2}+\sqrt{3}} + \frac{1}{\sqrt{3}+\sqrt{4}} + \ldots$$ upto 15 terms is
(1) 1
(2) 2
(3) 3
(4) 4

The sum of the series: $1 + \frac { 1 } { 1 + 2 } + \frac { 1 } { 1 + 2 + 3 } + \ldots\ldots$. upto 10 terms, is:
(1) $\frac { 18 } { 11 }$
(2) $\frac { 22 } { 13 }$
(3) $\frac { 20 } { 11 }$
(4) $\frac { 16 } { 9 }$

The sum of the series : $( 2 ) ^ { 2 } + 2 ( 4 ) ^ { 2 } + 3 ( 6 ) ^ { 2 } + \ldots$ upto 10 terms is :
(1) 11300
(2) 11200
(3) 12100
(4) 12300

The value of $1^{2} + 3^{2} + 5^{2} + \cdots + 25^{2}$ is:
(1) 2925
(2) 1469
(3) 1728
(4) 1456

If the sum of the first ten terms of the series $\left(1\frac{3}{5}\right)^{2}+\left(2\frac{2}{5}\right)^{2}+\left(3\frac{1}{5}\right)^{2}+4^{2}+\left(4\frac{4}{5}\right)^{2}+\ldots$, is $\frac{16}{5} m$, then $m$ is equal to: (1) 102 (2) 101 (3) 100 (4) 99

Let $S _ { k } = \frac { 1 + 2 + 3 + \ldots + k } { k }$. If $S _ { 1 } ^ { 2 } + S _ { 2 } ^ { 2 } + \ldots + S _ { 10 } ^ { 2 } = \frac { 5 } { 12 } A$, then $A$ is equal to :
(1) 301
(2) 303
(3) 156
(4) 283

If $n \geqslant 2$ is a positive integer, then the sum of the series ${ } ^ { n + 1 } C _ { 2 } + 2 \left( { } ^ { 2 } C _ { 2 } + { } ^ { 3 } C _ { 2 } + { } ^ { 4 } C _ { 2 } + \ldots + { } ^ { n } C _ { 2 } \right)$ is
(1) $\frac { n ( n - 1 ) ( 2 n + 1 ) } { 6 }$
(2) $\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 }$
(3) $\frac { n ( n + 1 ) ^ { 2 } ( n + 2 ) } { 12 }$
(4) $\frac { n ( 2 n + 1 ) ( 3 n + 1 ) } { 6 }$

The sum of the series $\sum _ { n = 1 } ^ { \infty } \frac { n ^ { 2 } + 6 n + 10 } { ( 2 n + 1 ) ! }$ is equal to
(1) $\frac { 41 } { 8 } e + \frac { 19 } { 8 } e ^ { - 1 } + 10$
(2) $\frac { 41 } { 8 } e + \frac { 19 } { 8 } e ^ { - 1 } - 10$
(3) $- \frac { 41 } { 8 } e + \frac { 19 } { 8 } e ^ { - 1 } - 10$
(4) $\frac { 41 } { 8 } e - \frac { 19 } { 8 } e ^ { - 1 } - 10$

If $\cot ^ { - 1 } ( \alpha ) = \cot ^ { - 1 } 2 + \cot ^ { - 1 } 8 + \cot ^ { - 1 } 18 + \cot ^ { - 1 } 32 + \ldots$ upto 100 terms, then $\alpha$ is:
(1) 1.01
(2) 1.00
(3) 1.02
(4) 1.03

$\frac { 1 } { 3 ^ { 2 } - 1 } + \frac { 1 } { 5 ^ { 2 } - 1 } + \frac { 1 } { 7 ^ { 2 } - 1 } + \ldots + \frac { 1 } { ( 201 ) ^ { 2 } - 1 }$ is equal to
(1) $\frac { 101 } { 404 }$
(2) $\frac { 25 } { 101 }$
(3) $\frac { 101 } { 408 }$
(4) $\frac { 99 } { 400 }$

If $[ x ]$ be the greatest integer less than or equal to $x$, then $\sum _ { n = 8 } ^ { 100 } \left[ \frac { ( - 1 ) ^ { n } n } { 2 } \right]$ is equal to:
(1) 0
(2) 4
(3) - 2
(4) 2

Let $S _ { n } = 1 \cdot ( n - 1 ) + 2 \cdot ( n - 2 ) + 3 \cdot ( n - 3 ) + \ldots + ( n - 1 ) \cdot 1 , \quad n \geqslant 4$. The sum $\sum _ { n = 4 } ^ { \infty } \frac { 2 S _ { n } } { n ! } - \frac { 1 } { ( n - 2 ) ! }$ is equal to :
(1) $\frac { e - 2 } { 6 }$
(2) $\frac { e - 1 } { 3 }$
(3) $\frac { e } { 6 }$
(4) $\frac { \mathrm { e } } { 3 }$

The sum of the series $\frac { 1 } { x + 1 } + \frac { 2 } { x ^ { 2 } + 1 } + \frac { 2 ^ { 2 } } { x ^ { 4 } + 1 } + \ldots + \frac { 2 ^ { 100 } } { x ^ { 2 ^ { 100 } } + 1 }$ when $x = 2$ is:
(1) $1 - \frac { 2 ^ { 101 } } { 4 ^ { 101 } - 1 }$
(2) $1 + \frac { 2 ^ { 101 } } { 4 ^ { 101 } - 1 }$
(3) $1 + \frac { 2 ^ { 100 } } { 4 ^ { 101 } - 1 }$
(4) $1 - \frac { 2 ^ { 100 } } { 4 ^ { 201 } - 1 }$

If $0 < x < 1$ and $y = \frac { 1 } { 2 } x ^ { 2 } + \frac { 2 } { 3 } x ^ { 3 } + \frac { 3 } { 4 } x ^ { 4 } + \ldots \ldots$, then the value of $e ^ { 1 + y }$ at $x = \frac { 1 } { 2 }$ is: (1) $\frac { 1 } { 2 } e ^ { 2 }$ (2) $2 e$ (3) $2 e ^ { 2 }$ (4) $\frac { 1 } { 2 } \sqrt { \mathrm { e } }$

If $A = \sum _ { n = 1 } ^ { \infty } \frac { 1 } { \left( 3 + ( - 1 ) ^ { n } \right) ^ { n } }$ and $B = \sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n } } { \left( 3 + ( - 1 ) ^ { n } \right) ^ { n } }$, then $\frac { A } { B }$ is equal to
(1) $\frac { 11 } { 9 }$
(2) 1
(3) $- \frac { 11 } { 9 }$
(4) $- \frac { 11 } { 3 }$

The sum $\sum_{n=1}^{21} \frac{3}{(4n-1)(4n+3)}$ is equal to
(1) $\frac{7}{87}$
(2) $\frac{7}{29}$
(3) $\frac{14}{87}$
(4) $\frac{21}{29}$

$\sum_{r=1}^{20} (r^2 + 1) \cdot r!$ is equal to
(1) $22! - 21!$
(2) $22! - 2 \cdot 21!$
(3) $21! - 2 \cdot 20!$
(4) $21! - 20!$

If $\frac { 1 ^ { 3 } + 2 ^ { 3 } + 3 ^ { 3 } \ldots\ldots \text { upto } n \text { terms } } { 1 \cdot 3 + 2 \cdot 5 + 3 \cdot 7 + \ldots.. \text { upto } n \text { terms } } = \frac { 9 } { 5 }$ then the value of $n$ is

If $a_n = \frac{-2}{4n^2 - 16n + 15}$, then $a_1 + a_2 + \ldots + a_{25}$ is equal to:
(1) $\frac{51}{144}$
(2) $\frac{49}{138}$
(3) $\frac{50}{141}$
(4) $\frac{52}{147}$

The sum $1^2 - 2 \cdot 3^2 + 3 \cdot 5^2 - 4 \cdot 7^2 + 5 \cdot 9^2 - \ldots + 15 \cdot 29^2$ is $\_\_\_\_$.

Let $a _ { n }$ be $n ^ { \text {th} }$ term of the series $5 + 8 + 14 + 23 + 35 + 50 + \ldots\ldots$. and $S _ { n } = \sum _ { k = 1 } ^ { n } a _ { k }$. Then $S _ { 30 } - a _ { 40 }$ is equal to
(1) 11310
(2) 11260
(3) 11290
(4) 11280

If $S _ { n } = 4 + 11 + 21 + 34 + 50 + \ldots$ to $n$ terms, then $\frac { 1 } { 60 } \left( S _ { 29 } - S _ { 9 } \right)$ is equal to
(1) 223
(2) 226
(3) 220
(4) 227

The sum of the series $\frac{1}{1 \cdot 3} + \frac{1}{3 \cdot 5} + \frac{1}{5 \cdot 7} + \cdots + \frac{1}{(2n-1)(2n+1)}$ is $\_\_\_\_$.

The sum of the series $\frac { 1 } { 1 - 3 \cdot 1 ^ { 2 } + 1 ^ { 4 } } + \frac { 2 } { 1 - 3 \cdot 2 ^ { 2 } + 2 ^ { 4 } } + \frac { 3 } { 1 - 3 \cdot 3 ^ { 2 } + 3 ^ { 4 } } +\ldots$ up to 10 terms is
(1) $\frac { 45 } { 109 }$
(2) $- \frac { 45 } { 109 }$
(3) $\frac { 55 } { 109 }$
(4) $- \frac { 55 } { 109 }$